Is x relative to x0 here (i.e. x = t or s)? I find it easier to interpret interpolation when rewriting it as: xv1 + (1-x)v0 where 0 <= x <= 1. This makes it easy to see that we are mixing v0 and v1.
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Is x relative to x0 here (i.e. x = t or s)? I find it easier to interpret interpolation when rewriting it as: xv1 + (1-x)v0 where 0 <= x <= 1. This makes it easy to see that we are mixing v0 and v1.